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9g=-24g^2+15
We move all terms to the left:
9g-(-24g^2+15)=0
We get rid of parentheses
24g^2+9g-15=0
a = 24; b = 9; c = -15;
Δ = b2-4ac
Δ = 92-4·24·(-15)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-39}{2*24}=\frac{-48}{48} =-1 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+39}{2*24}=\frac{30}{48} =5/8 $
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